3[a+1]=19-5a

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Solution for 3[a+1]=19-5a equation:


Simplifying
3[a + 1] = 19 + -5a

Reorder the terms:
3[1 + a] = 19 + -5a
[1 * 3 + a * 3] = 19 + -5a
[3 + 3a] = 19 + -5a

Solving
3 + 3a = 19 + -5a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5a' to each side of the equation.
3 + 3a + 5a = 19 + -5a + 5a

Combine like terms: 3a + 5a = 8a
3 + 8a = 19 + -5a + 5a

Combine like terms: -5a + 5a = 0
3 + 8a = 19 + 0
3 + 8a = 19

Add '-3' to each side of the equation.
3 + -3 + 8a = 19 + -3

Combine like terms: 3 + -3 = 0
0 + 8a = 19 + -3
8a = 19 + -3

Combine like terms: 19 + -3 = 16
8a = 16

Divide each side by '8'.
a = 2

Simplifying
a = 2

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